Задание 24. Информатика. ЕГЭ. Поляков-6050

Python

def is_good(st):
    s1 = 'DANOV'
    return sum(x != y for x, y in zip(s1, st)) != 1

s = open('6050.txt').readline().strip()
ml = 0
p0 = -1
for p in range(4, len(s)):
    if not is_good(s[p-4:p+1]):
        ml = max(ml, p - 1 - p0)
        p0 = p - 4
ml = max(ml, len(s) - 1 - p0)
print(ml)

Ответ: \(229549\)