Задание 24. Информатика. ЕГЭ. Поляков-6526

Python

s = open('6526.txt').readline().strip()
pa = [x for x in range(len(s)) if s[x:x+3] == 'ATG']

ml = 0
for p in pa:
    p1 = s.find('TAA', p)
    while p1 != -1:
        if all(s[p+3:p1].count(tr) == 0 for tr in ('TAA', 'TGA', 'TAG')):
            ml = max(ml, p1 - p + 3)
        else:
            break
        p1 = s.find('TAA', p1 + 1)

print(ml)

Ответ: \(124\)