Задание 24. Информатика. ЕГЭ. Поляков-7999

Python

from re import finditer

def is_prime(n):
    if n < 2:
        return False
    if n == 2:
        return True
    for i in range(2, int(n ** 0.5) + 1):
        if n % i == 0:
            return False
    return True

s = open('7993.txt').readline().strip()
arr = []
n = r'(0|[1-9][0-9]*)'
for g in finditer(rf'{n}(={n})+', s):
    tmp = g.group(0).split('=')
    lt = len(tmp)
    if any(len(x) == 4 and is_prime(int(x)) for x in tmp):
        arr.append(len(g.group(0)))
    else:
        tmp1 = g.group(0)[::-1].split('=')
        lt = len(tmp)
        for k, t in enumerate((tmp, tmp1)):
            for i in range(lt - 1):
                curr = t[i]
                if len(curr) > 4:
                    st = curr[-4:] if k == 0 else curr[-4:][::-1]
                    if is_prime(int(st)):
                        stmp = '='.join(t[i+1:])
                        arr.append(len(stmp) + 5)
print(max(arr))

Ответ: \(999\)