Задание 8. Информатика. ЕГЭ 2026. Крылов. Вариант 10

Решение через itertools

Python

from itertools import product

s = list('РЕПЛИКА')
s.sort()
q = 0

for i, word in enumerate(product(s, repeat=6), 1):
    q += i % 2 == 0 and word[0] != 'К' and word.count('И') > 1
print(q)

Старое решение

Python

s = [ch for ch in 'РЕПЛИКА']
s.sort()
i = 0
count = 0

for a in s:
    for b in s:
        for c in s:
            for d in s:
                for e in s:
                    for f in s:
                        word = a+b+c+d+e+f
                        i += 1
                        if i % 2 == 0 and a != 'К' and word.count('И') > 1:
                            count += 1

print(count)

Ответ: \(10892\)