Задание 8. Информатика. ЕГЭ 2026. Крылов. Вариант 13

Решение через itertools

Python

from itertools import product

alph = '01234567'
deny = ('41', '43', '45' ,'47', '14', '34', '54', '74')
q = 0

for nums in product(alph, repeat=5):
    n = ''.join(nums)
    q += nums[0] != '0' and nums.count('4') == 2 \
         and all(c not in n for c in deny)
print(q)

Старое решение

Python

alpha = '01234567'
q = 0

deny = ('14', '34', '54', '74', '41', '43', '45', '47')

for a in alpha[1:]:
    for b in alpha:
        for c in alpha:
            for d in alpha:
                for e in alpha:
                    num = a + b + c + d + e
                    if num.count('4') == 2 and all([x not in num for x in deny]):
                        q += 1

print(q)

Ответ: \(612\)