Задание 8. Информатика. ЕГЭ 2026. Крылов. Вариант 14

Решение с помощью itertools

Python

from itertools import product

alph = '0123'
q = 0

for nums in product(alph, repeat=5):
    n = ''.join(nums)
    q += nums[0] != '0' and nums.count('3') == 1 \
         and all(c not in n for c in ('03', '30'))
print(q)

Старое решение

Python

alpha = '0123'
q = 0

for a in alpha[1:]:
    for b in alpha:
        for c in alpha:
            for d in alpha:
                for e in alpha:
                    num = a + b + c + d + e
                    if num.count('3') == 1 and '30' not in num and '03' not in num:
                        q += 1

print(q)

Ответ: \(174\)